Dam-break problem with water, oil, and mercury (High resolution mesh)
Case directory
$FOAM_TUTORIALS/multiphase/multiphaseInterFoam/laminar/damBreak4phaseFine
Summary
Model geometry
We calculate a dam-break problem with three liquids: water, oil, and mercury, for 6 seconds. The calculation is performed as a two-dimensional problem with a single mesh in the Z direction.
The properties and interactions of each fluid are specified in the file "constant/transportProperties" as follows where nu is the kinematic viscosity (m2/s), rho is the density (kg/m3), and sigmas is the surface tension between the fluids.
phases
(
water
{
transportModel Newtonian;
nu [0 2 -1 0 0 0 0] 1e-06;
rho [1 -3 0 0 0 0 0] 1000;
}
oil
{
transportModel Newtonian;
nu [0 2 -1 0 0 0 0] 1e-06;
rho [1 -3 0 0 0 0 0] 500;
}
mercury
{
transportModel Newtonian;
nu [0 2 -1 0 0 0 0] 1.125e-07;
rho [1 -3 0 0 0 0 0] 13529;
}
air
{
transportModel Newtonian;
nu [0 2 -1 0 0 0 0] 1.48e-05;
rho [1 -3 0 0 0 0 0] 1;
}
);
sigmas
(
(air water) 0.07
(air oil) 0.07
(air mercury) 0.07
(water oil) 0.07
(water mercury) 0.07
(oil mercury) 0.07
);
The meshes are as follows, and the number of mesh is 34200.
Meshes
Meshes (front view)
The calculation result is as follows.
The ID values of each fluid are as follows.
- Water: 0.0
- Oil: 1.0
- Mercury: 2.0
- Air: 3.0
Fluids at initial time (alphas)
Fluids at 0.75 sec (alphas)
Fluids at final time (alphas)
At final time, we can see that each fluid is divided into layers by density.
Commands
cd damBreak4phaseFine
cp -r 0.orig 0
blockMesh
setFields
decomposePar
mpirun -np 4 multiphaseInterFoam -parallel
reconstructPar
paraFoam
Calculation time
48 minutes 52.74 seconds *4 parallel, Inter(R) Core(TM) i7-2600 CPU @ 3.40GHz 3.40GHz